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Question

Write programs to print following patterns :

**********
**********
**********
**********
        

*
**
***
****
*****
        

    *
   **
  ***
 ****
*****
        

    *
   ***
  *****
 *******
*********
        

    1
   222
  33333
 4444444
555555555
        

    1
   212
  32123
 4321234
543212345
        

1.

Source Code

#include <stdio.h>

int main()
{
    int i, j;

    for (i = 1; i <= 4; i++)
    {
        for (j = 1; j <= 10; j++)
        {
            printf("*");
        }
        printf("\n");
    }

    return 0;
}

2.

Source Code

#include <stdio.h>

int main()
{
    int i, j;

    for (i = 1; i <= 5; i++)
    {
        for (j = 1; j <= i; j++)
        {
            printf("*");
        }
        printf("\n");
    }

    return 0;
}

3.

Source Code

#include <stdio.h>

int main()
{
    int i, j, k;

    for (i = 1; i <= 5; i++)
    {
        for (j = 5; j > i; j--)
        {
            printf(" ");
        }
        for (k = 1; k <= i; k++)
        {
            printf("*");
        }
        printf("\n");
    }

    return 0;
}

4.

Source Code

#include <stdio.h>

int main()
{
    int i, j, k;

    for (i = 1; i <= 5; i++)
    {
        for (j = 5; j > i; j--)
        {
            printf(" ");
        }
        for (k = 1; k <= 2 * i - 1; k++)
        {
            printf("*");
        }
        printf("\n");
    }

    return 0;
}

5.

Source Code

#include <stdio.h>

int main()
{
    int i, j, k;

    for (i = 1; i <= 5; i++)
    {
        for (j = 5; j > i; j--)
        {
            printf(" ");
        }
        for (k = 1; k <= 2 * i - 1; k++)
        {
            printf("%d", i);
        }
        printf("\n");
    }

    return 0;
}

6.

Source Code

#include <stdio.h>

int main()
{
    int i, j, k, l;
    
    for (i = 1; i <= 5; i++)
    {
        for (j = 5; j > i; j--)
        {
            printf(" ");
        }
        for (k = i; k >= 1; k--)
        {
            printf("%d", k);
        }
        for (l = 2; l <= i; l++)
        {
            printf("%d", l);
        }
        printf("\n");
    }

    return 0;
}